When an aqueous solution of cupric bromide is | vedclass

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(B) During the electrolysis of an aqueous solution of cupric bromide $(CuBr_2)$,the ions present are $Cu^{2+}$,$Br^-$,$H^+$,and $OH^-$.At the cathode,

Vedclass · Accepted Answer

$Cu$

Vedclass · Answer

(B) During the electrolysis of an aqueous solution of cupric bromide $(CuBr_2)$,the ions present are $Cu^{2+}$,$Br^-$,$H^+$,and $OH^-$.At the cathode,the reduction reaction occurs. The discharge potential of $Cu^{2+}$ $(E^0 = +0.34 \ V)$ is lower than that of $H^+$ ions $(E^0 = 0.00 \ V)$.Therefore,$Cu^{2+}$ ions are preferentially reduced at the cathode to form metallic copper $(Cu)$.The reaction at the cathode is: $Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)$.

When an aqueous solution of cupric bromide is electrolyzed,the product obtained at the cathode will be:

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